Amit Kumar

This page lists questions and answers that were posted by visitors named Amit Kumar.

Questions

The following questions were asked by visitors named Amit Kumar.

Answers

The following answers were posted by visitors named Amit Kumar.

initial pressure of the air(P1) = 762mm Hg P2 = ? T1 = 25.7+273 = 298.7K T2 = 38.8+273 = 311.8K P2 =? P2 = 762 mm Hg x 311.8K/298.7K = 795.42 mm Hg so, pressure of ethanol = 980 - 795.42 = 184.58 mm Hg Answer in three sig fig will be 184 mm Hg.