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Questions and answers by
Amit Kumar
Answers (2)
Wright
initial pressure of the air(P1) = 762mm Hg P2 = ? T1 = 25.7+273 = 298.7K T2 = 38.8+273 = 311.8K P2 =? P2 = 762 mm Hg x 311.8K/298.7K = 795.42 mm Hg so, pressure of ethanol = 980 - 795.42 = 184.58 mm Hg Answer in three sig fig will be 184 mm Hg.
