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Questions and answers by
Aman keshari
Answers (1)
tan(3A+A) = (tan3A + tanA)/(1-tan3AtanA) tan(3A-A) = (tan3A - tanA)/(1+tan3AtanA) add them, and you have a common denominator of (1-tan²3Atan²A) numerator = (tan3A + tanA)(1+tan3AtanA) + (tan3A - tanA)(1-tan3AtanA) = 2(tan3A + tan3Atan²A) =
