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Alveena Khan
Questions (2)
A train is moving with 72 kmh−1speed. The driver applies the brakes and the train decelerates with 1.3 ms−2and takes 25
2 answers
510 views
A train is moving with 72 kmh−1speed. The driver applies the brakes and the train decelerates with 1.3 ms−2 and takes 25
1 answer
275 views
Answers (1)
Given values are vi=72kmsec−1=20msec−1 vf=0ms-1 a=−1.3msec−2 t=25sec Use second equation of motion to find traveled distance before stopping. S=Vit+1/2 at2 S=(20)x(25)+1/2(-0.3)(25)2 S=93.75m
