Answers by visitors named: Aerin

I do believe the x = 12. Because the area of the painting and the frame is 208 FT^2 and the thickness of the frame is 1 foot. The dimensions of the painting are x by x+3, so they are x^2+3x. The dimensions of the painting and the frame therefore must be x...

Okay. I just realized something. X will equal 11 and the dimensions would be 11 by 14 because the width of the frame would have to be considered twice. So the dimensions of the painting and the frame altogether would be (x+2)(x+5). The dimensions of the p...