Aditya, Phd Maths

This page lists questions and answers that were posted by visitors named Aditya, Phd Maths.

Questions

The following questions were asked by visitors named Aditya, Phd Maths.

Answers

The following answers were posted by visitors named Aditya, Phd Maths.

A=P(1+r/n)^(nt) P=3500, r=4%=0.04,t=3,n=1 A=3500(1+(0.04/1))^(3×1)=3500(1.04)^3 A=3500(1.124864)=3937.024=3937.00 (rounded to nearest cent)
2 years ago