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Aditi Arya
Questions (1)
The rate constant of a certain reaction is given by log K= 212/T Calculate the activation energy at 400K.
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Answers (1)
let the smaller number be x. Then the larger number will be x+6. Now according to the question; 2(x+6) +10=3x-2 2x+ 12+ 10=3x-2 3x-2x=12+10+2 x=24 and the larger number will be (24+6)=30.
