Answers by visitors named: Acezar

Nevermind, I figured it out: The quotient: (10x^6 - 15x^5 - 5x^3)/(5x^3 ) (10x^6)/(5x^3 ) - (15x^5)/(5x^3 ) - (5x^3)/(5x^3 ) 2x3 - (15x^5)/(5x^3 ) - (5x^3)/(5x^3 ) 2x3 - 3x2 - (5x^3)/(5x^3 ) 2x3 - 3x2 - 1 The product using the quotient: (x2 - 3x + 5)(2x3 - 3x2 - 1) x2 ∙ 2x3 + x2 ∙ -3x2 + x2 ∙ - 1 - 3x ∙ 2x3 - 3x ∙ -3x2 - 3x ∙ -1 + 5 ∙ 2x3 + 5 ∙ -3x2 + 5 ∙ -1 2x5 - 9x4 + 19x3 - 16x2 + 3x - 5

Here's a better format. Good luck to anyone else who has this problem. The quotient: (10x^6 - 15x^5 - 5x^3)/(5x^3 ) (10x^6)/(5x^3 ) - (15x^5)/(5x^3 ) - (5x^3)/(5x^3 ) 2x^3 - (15x^5)/(5x^3 ) - (5x^3)/(5x^3 ) 2x^3 - 3x^2 - (5x^3)/(5x^3 ) 2x^3 - 3x^2 - 1 The product using the quotient: (x^2 - 3x + 5)(2x^3 - 3x^2 - 1) x^2 * 2x^3 + x^2 * -3x^2 + x^2 * - 1 - 3x * 2x^3 - 3x * -3x^2 - 3x * -1 + 5 * 2x^3 + 5 * -3x^2 + 5 * -1 2x^5 - 9x^4 + 19x^3 - 16x^2 + 3x - 5

The idea is to solve the quotient first, by dividing each term by 5x^3. Once the solution is found: 2x^3 - 3x^2 - 1 Then use that quotient and multiply it by (x^2 - 3x + 5). Thus: (x^2 - 3x + 5)(2x^3 - 3x^2 - 1)