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Find the product of (x^2 - 3x + 5) with the quotient of (10x^6 - 15x^5 - 5x^3) ÷ 5x^3.I need some help with this. I'm really
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The idea is to solve the quotient first, by dividing each term by 5x^3. Once the solution is found: 2x^3 - 3x^2 - 1 Then use that quotient and multiply it by (x^2 - 3x + 5). Thus: (x^2 - 3x + 5)(2x^3 - 3x^2 - 1)
Here's a better format. Good luck to anyone else who has this problem. The quotient: (10x^6 - 15x^5 - 5x^3)/(5x^3 ) (10x^6)/(5x^3 ) - (15x^5)/(5x^3 ) - (5x^3)/(5x^3 ) 2x^3 - (15x^5)/(5x^3 ) - (5x^3)/(5x^3 ) 2x^3 - 3x^2 - (5x^3)/(5x^3 ) 2x^3 - 3x^2 - 1 The
Nevermind, I figured it out: The quotient: (10x^6 - 15x^5 - 5x^3)/(5x^3 ) (10x^6)/(5x^3 ) - (15x^5)/(5x^3 ) - (5x^3)/(5x^3 ) 2x3 - (15x^5)/(5x^3 ) - (5x^3)/(5x^3 ) 2x3 - 3x2 - (5x^3)/(5x^3 ) 2x3 - 3x2 - 1 The product using the quotient: (x2 - 3x + 5)(2x3 -

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