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Aboubakar
Answers (1)
Since the collision is elastic then kinetic energy will be constant......1/2m1v1^2=1/2m1v1^2+1/m2v2^2..... Given m1=m By combining the equations and making v1 the subject V1=[{v1(m1-m2)}+(2m2*v2)]/(m1+m2) Note:v2=0 after computing..the mass of the second
