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Given: mass of solute = 3.75 g mass of solvent = 95 g = 0.095 kg boiling point of solvent = 55.95°C boiling point of solution = 56.50°C Kb = 1.71°C·kg/mol . Moles of acetone = \frac{95}{58}=1.64 moled 58 95 =1.64moled Molarity =
