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hi!
ok, i know that deriv(cscx) = -cscxcotx and that deriv(cos) = -sinx deriv(cotx) = -((cscx)^2) my question is: is this
1 answer
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Hi! Thank you very much!
My question is: how do you find the antiderivative of 1 / (square root[1-(x^2)]) aka antideriv(
1 answer
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I am not sure how to approach this...I have to find the value of x that makes the derivate of f(x) equal to zero...here's what I
1 answer
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How do I find the derivative of
x^ (1/(x-1)) is it (1/(x-1)) x^[1-(1/(x-1))] * (-1/ (x-1)^2) ?? If not, can you please write out
2 answers
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