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Questions (19)
Someone said, "Calculate the total delta H of the reaction and subtract the total delta H of the product from it. If you get a
1 answer
597 views
C6H14 + 19/2 O2 -> 6 CO2 + 7H2O delta H = -4163 kJ
What mass of hexane is required to produce 1.0E5 kJ of heat by complete
1 answer
804 views
Someone said, "Calculate the total delta H of the reaction and subtract the total delta H of the product from it. If you get a
0 answers
676 views
HCl (aq) + NaOH (aq) -> NaCl (aq) + H2O (l)
Will the neutralisation reaction be endothermic or exothermic? Hint: think about the
2 answers
2,174 views
Are my answers correct?
C6H14 + 19/2 O2 -> 6 CO2 + 7H2O enthalpy change = -4163 kJ a) if 0.537 mol of carbon dioxide is produced
3 answers
4,197 views
2C2H2 + 5O2 -> 4CO2 + 2H2O + energy
What does the equation communicate about the relative energy of the chemical bonds in the
3 answers
2,616 views
Please help me figure out where I went wrong.
HNO3 + KOH -> KNO3 + H2O enthalpy change = -53.4 kJ/mol 55.0 mL of 1.30 mol/L
3 answers
2,783 views
I don't really understand why unit analysis works.
I found a simple example on a website (I can post the link in a comment if you
4 answers
778 views
4Fe + 3O2 -> 2Fe2O3 + 1.65E3 kJ
C) what is the enthalpy change for the formation of 23.6 g of iron(iii) oxide? I'm trying to
1 answer
3,154 views
25.9 kJ + 1/2 H2 + 1/2 I2 -> HI
B) how much energy is needed for the reaction of 4.57E24 molecules of iodine, I2, with excess
1 answer
1,801 views
4Fe + 3O2 -> 2Fe2O3 + 1.65E3 kJ
C) what is the enthalpy change for the formation of 23.6 g of iron(iii) oxide? I'm trying to
0 answers
1,763 views
This isn't exactly a homework question, I'm just trying to understand the concept we learned today...
So say we had: 4Fe + 3O2
8 answers
881 views
N2 + O2 -> 2NO enthalpy change = +180.6kJ
c) what is the enthalpy change for the formation of one mole of nitrogen monoxide?
1 answer
1,872 views
How come the formula for potassium peroxide is K2O2; I can't see how you'd get that...
1 answer
2,986 views
Why is the formula for potassium peroxide K2O2?
0 answers
745 views
The height of a plant after each of the first three weeks was 7mm, 20mm, and 33mm, respectively. If this pattern of growth
1 answer
570 views
The height of a plant after each of the first three weeks was 7mm, 20mm, and 33mm, respectively. If this pattern of growth
0 answers
567 views
In a lab experiment, the count of a bacteria doubles every hour.
a)at 1pm, there was 23000 bacteria. How many bacteria will be
1 answer
1,152 views
The height of a plant after each of the first three weeks was 7mm, 20mm, and 33mm, respectively. If this pattern of growth
0 answers
566 views
Answers (11)
Sorry, how would you solve for mols? I feel like this should be obvious, but ...
If you absolutely had to improve it what would you improve? Anything that sticks out especially to you But thank you; haha, I wouldn't go after an American prize anyways!
I checked it over for what feels like the tenth time and I see that I should've converted the 3.82 kJ to 3820 J; I ended up with the correct answer using that. But I feel like my method was a bit over-complicated. Is there a simpler method that I'm just
I just realised I made the stupidest mistake ever. I guess this is what happens when you try to do chemistry while sick. The last bit of math doesn't make sense; it should be 3.82 = (460.24)(Tf-21.4°C) 3.82 = Tf460.24 - 9849.136 -Tf460.24 = -9849.136 -
, but then would 1mol/18g H2O mean 1 mol per 18 grams per mol of H2O..? There's one mol for every 18g of H2O..? It's confusing
But I don't think division would mean "which" weighs 18g..
I'm really sorry, but I still don't really understand - what do you mean by "figure out what part of two moles you had "?
Thanks for answering!! "Now for 23.6g FeOxide, you do not have two moles, you have to figure what part of the energy you get." Could you clarify what you mean by that? I think this is closer to answering and fixing my confusion; what do you mean by "what
Sorry, I posted the above before I got to see your answer, bobpursley. I think I get it a little more but could you clarify a bit more based on what I asked above?
Okay so after some trial and error (I just kept trying different things Until I got the answer), I figured out it's *probably* solved like this: Enthalpy = 23.6g Fe2O3 x 1 mol Fe2O3/[(2x56) + (3x16)]g x -1.65x10^3 kJ/2 mol Fe2O3 = -1.22 x 10^2 kJ If that's
Whoops, never mind, I got the answer.