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51705 MCL student
Answers (1)
A=L*W P=L*2W three sides 600m=L*2W L=600-2W substitute in the area A=(600-2W)*W A=600W-2W^2 convert the eq. to vertex form y=a(x-h)^2+k A=-2W^2+600W complete the square A=-2(W^2-300W+22500)+22500*2 A=(W-150)^45000 w=150 substitute calculate.... L=600-2w
