124

This page lists questions and answers that were posted by visitors named 124.

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The following questions were asked by visitors named 124.

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The following answers were posted by visitors named 124.

9b = 9a, E1 = V/d1 and E2 = V/d2 9c)try with charge conservation

P, phi=B*w*(L-z) |em|=|dphi/dt|=B*w*V i=|em|/R=B*w*V/R F=watt/ms^-1=(|em|^2/R)*1/V

10b)= frequency that abs(i(t))=max

i(t)=I0*cos(w*t) and abs(i(t))=max if w*t=k*pi, for k=1=>t1=pi/w f=1/t1=w/pi=1/(pi*sqrt(L*C))

10d)=>average p=v*i on [0,3*t1]

BG, S=E*B/mu_0 = 1/(2*pi^2*b)*s^2*t/(b^2-a^2)

10b) f=1/t1=w/pi=1/(pi*sqrt(L*C))

BG, B(r=b) = mu_0*s/(2*pi*b)is not the the previous B(r)

robbo, v=Ldi/dt P_mean=1/(3T-0)*int(v*i,0,3*T) T=2*pi*sqrt(L*C) 11c)e)=>Q_net+ q = Q_encl in the gauss Law

robbo, formula is right, check s^2*t for example s=24u and t=5u s^2*t = 24*24*5*1u^3

Jack, yes the formula is OK

robbo,sorry i forgot e_0 (1u*12u^2)/(2*(PI^2)*5.3m*(5.3m^2-1.4m^2)*8.85e-12) =5.95215457341 E =|E|er |E|=1/(4*pi*e_0*kappa)*q/r^2 for (a<r<b) |E|=1/(4*pi*e_0)*q/r^2 for r>=b

S=E*B/mu_0 = 1/(2*pi^2*b*epsilon_0)*(s^2)*(t/(b^2-a^2))

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10d) P=1/3T * int(-L*w*(Imax)^2*sin(wt)*cos(wt), 0 , 3T) = 0!!!!! T=2*pi*sqrt(L*C)

it seems that we cheated. So I leave. Good luck to all!