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007

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An atom emits a photon of wavelength 1.08 meters. What is the energy change occurring in the atom due to this emission?
1. 1 answer
2. 528 views
A boy walked for 4 hours and cycled for 3 hours,covering a total distance of 74 kilometers,later he walked for 2 hours and
1. 1 answer
2. 928 views

Faith is right, but maybe a came here for help not answers. I still agree with u faith but...
random is correct, trust me
y u all cheat?
ms sue is not mean she is honest. you guys are the ones cheating.
I am not trying to be irrelevant or saying the wrong answer, but wouldnt 30 work because the people there could speak over 1,000 and 1,000 is more than 30
3 is wrong the good answers are 1=b 2=d 3=a 4=a
Are you sure its 42?
Some help please. I really don't know what is my error
I worked with this equation: sigma=C_2*E_s*0.1^2 = 750000[Pa] Then for the energy: U=sigma*s_densification= 750000*0.8=600000[J/m^3] But the answer is incorrect. Also, I know that E=C_1*E_s*0.1^2 =15[MPa] But I don't know how can I use it. Some help please
I am having problems with the first part. Because I found the deflection as: delta=((P*(l_AB)^2)*((3*(l))-l_AB))/(6*E*I) But l is not permitted, so I replaced l=0.95[m]. but I obtained a wrong answer. My deduction is correct? What is my error? Please, some
3....MPa use this equation (sigma)max=(sigma)avg+R
008
Haha, I'm stuck on this one too.
thanx you helped me

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