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.E.A.A.Dammy
Answers (3)
or having your parameters and area you can solve it like dis p=RA/L =0.000000196/1.0 =0.000000392 or 3.92*10^-7 check for the post of the parameters on the post by E.A.A. DAMMY
I have already posted the answer here is the question what is the resistivity of a cylindrical material wire whose length is 1.0 metre and has a resistance of 2.0ohms and a diameter of 0.5mm don't forget the unit ohmmeters thanks
length=1.0 metre resistance=2.0 ohms diameter= 0.5mm=0.0005m=5*10^-4 radius = diameter/2 =0.5/2mm=0.25mm=0.00025m=2.5*10^-4 area= pi*r^2= 22/7 * (2.5* 10^-4)^2 =22/7*6.25*10^-8= 1.94*10^-7 substituting into the formula we have; R=p*l/a 2=p * 1.0/1.96*10^-7