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Einstein
Answers (1)
PE going into the down side: mgH KE is translational, and rotational or mgH=1/2 m v^2 + 1/2 Imr^2*w^2 mgH=1/2 m v^2 + 1/2 (1/2)mr^2*w^2 but when rolling, w=v/r mgH=1/2 m v^2+1/4*mv^2 On the second side, rolling doesn t happen, the shell just spins, and how