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𝖔𝖔𝖇𝖑𝖊𝖈𝖐

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sum=0 for i=1..100 read name[i],score[i] print name[i],score[i] sum += score[i] next i avg = sum/100 print avg
why post gibberish? "comes in either 25 ounce cans than the larger cans " is nonsense.
the inverse function for y= e^-0.0001210t found via ln y = -0.0001210t lny/-0.0001210 = t so y-1(t) = -1/0.0001210 ln(t) = -8264.46 ln(t)
opens downward from (-4,-7)
You need to solve e^-0.0001210t = 0.30 now, t=48000 is the answer, so your equation should be e^(-0.0001210 • 48000) = 0.30 The "t" is now gone, since that's what you solved for. so I guess you did it right ... Guess, because you didn't show your actual
log 0.5 is negative, so change the direction of the inequality
not really calculus - just Algebra II just plug in the value for t. e^(-0.0001210*1500) = 0.834 or 83.4%
3.3s * 1hr/3600s * 30km/hr * 1000m/km = (3.3*30*1000)/(3600) meters
per the usual formula, 18000(1.05^2 - 1)
twice a number ... 2x "decrease" means you subtract, so ...
If they both earn x, then 5/7 x = 1120 x = 1568 (2/7 + 3/8)*1568 = ____
o+k = 358 (5/7 o)/(k-35) = 2 now solve as usual

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