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@ oobleck ---- mathhelper
Answers (3)
according to the definition of an AP 2p-2 - (2p+1) = 4p-3 - (2p - 2) -3 = 2p -1 2p = -2 p = -1 check: if p = -1, the terms are -1, -4, -7 , which form an AP
Assuming digits may be repeated and you are talking about 1,2, and 3 as choices numer of formings = 3*3*3 = 27
Came across this: int main() { int answer {42}; std::cout
