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animuzi

@animuzi

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Weight of load: 2228 N Magnitude of force: 11,191 N 1. Write out the Parameters (Tension, beam mass, d, s, x, h) m= beam mass*d= 88.5 * 5.290 =465.5 kg find theta using arctan(opp/ adj) arctan (h/ (d-s)) = arctan (1.890/ (5.290- 0.594)) = 21.9 degrees
The goal is to isolate the variable by getting to q= .. Multiply both sides by 2. 3q = 10 Divide by 3 to isolate q. q= 10/3
In both cases, the force of friction is 12.7 N because the box won't move. It's just being pushed once and halts. Hope this helps: 𝑓≤𝜇s𝑁 This means that the force of static friction can take on any value from 0 to 𝜇𝑁. Normal force = mg

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