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y = (ln x)^(cos4x) Use

  1. Prove thatcos4x=8cos^4x-8cos^2x+1 so I'm guessing you begin with the left side cos4x=cos2(2x) then im kinda lost
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    2. Natash asked by Natash
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  2. Several questions from my homework, any are appreciated. Thanks!Solve: 1) sinx-tanx=0 2) 3csc^2x=4 Find all solutions within
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    2. Michael asked by Michael
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  3. Find all solutions to the equation in the interval [0, 2pi)cos4x-cos2x=0 So,this is what i've done so far: cos4x-cos2x=0
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    2. Maria asked by Maria
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  4. wat is the ans of this solutions?y=sin^4x cos4x? ^
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    2. andrea asked by andrea
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  5. Derivative of y=in((e^-2x)(cos4x))
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    2. DK asked by DK
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  6. Prove cos4x = 8 cos^4x-8 cos^2x+1
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    2. Dini asked by Dini
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  7. cos4x^2 + sin4x^2?
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    2. Patrick asked by Patrick
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  8. lim x→0 of [2-cos3x-cos4x]/(x)
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    2. tish asked by tish
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  9. Prove:cos4x = 8cos^4x - 8cos^2x + 1 My Attempt: RS: = 4cos^2x (2cos^2x - 1) + 1 = 4 cos^2x (cos2x) + 1 LS: = cos2(2x) =
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    2. Anonymous asked by Anonymous
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  10. 1.Ifg(x)=cos4x,find g'(pie/24).2.Differentiate y=csc^2 pie*x
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    2. albert asked by albert
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