y=1/2cos[1/2(x-30)]-5 has a mapping rule

y=1/2cos[1/2(x-30)]-5 has a mapping rule ofa. (1/2x-30, 1/2y-5) b. (2x-30, 1/2y-5) c. (2x-30, 2y-5) d. (2x+30, 1/2y-5)
1. 1 answer
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Given A = {1, 2, 3, 4} B = {2, 5, 10, 17}, a E A and b E BThe mapping rule for f maps 1 to 2, 2 to 5, 3 to 10 and 4 to 17. (A)
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2. asked by simon
3. 660 views
Given A = {1, 2, 3, 4} B = {2, 5, 10, 17}, a E A and b E BThe mapping rule for f maps 1 to 2, 2 to 5, 3 to 10 and 4 to 17 (b)
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2. asked by simon
3. 552 views
cosA= 5/9 find cos1/2Aare you familiar with the half-angle formulas? the one I would use here is cos A = 2cos^2 (1/2)A - 1 5/9 +
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2. asked by Anonymous
3. 793 views
What am I doing wrong?Equation: sin2x = 2cos2x Answers: 90 and 270 .... My Work: 2sin(x)cos(x) = 2cos(2x) sin(x) cos(x) =
1. 1 answer
2. asked by Anonymous
3. 951 views
how does 2cos(2x)-2cos(x)sin(x) becomes 2cos(2x)-sin(2x)? Try to explain each step simply.
1. 1 answer
2. 64 views
Determine the solution of the equetion: 2cos x-1=0? 2cos x=0? and 2cos x+1=0?
1. 3 answers
2. asked by Miley
3. 481 views
What is the rule of the mapping(1, 2), (2, 4), (3, 8), (4, 16), (5, 32).
1. 2 answers
2. asked by John
3. 140 views
Which statement describes the mapping?x, negative 1, 0, 2, 3, y, 1, 4, 7 The mapping represents y as a function of x, because
1. 1 answer
2. 80 views
Identify the equation for the following graph: (1 point) Responses y=2cos(2x) y is equal to 2 cosine 2 x y=−2cos(2x) y is
1. 1 answer
2. 87 views