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y= cosxtanx

  1. y= cosxtanx
    1. answers icon 1 answer
    2. jnky asked by jnky
    3. views icon 340 views
  2. How would you solve these questions using Trigonomic Identities?sin^2x = tan^2x/1+tan^2x sinx+cosx/tanx = 1/cosxtanx
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    2. O asked by O
    3. views icon 480 views
  3. Solve cosxtanx + root3cosx - root3/2tanx - 3/2 = 0exact answers and formula for general solution
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    2. don asked by don
    3. views icon 362 views
  4. solve cosxtanx + root3cosx - root3/2tanx - 3/2 = 0exact value answers and formula for the general solution and specific
    1. answers icon 1 answer
    2. don asked by don
    3. views icon 475 views
  5. Solve : cosxtanx + root3cosx - root3/2tanx - 3/2 = 0Give exact answers and formula for the general solution as well as the
    1. answers icon 0 answers
    2. Don asked by Don
    3. views icon 474 views
  6. Solve cosxtanx + sqroot3cosx - sqroot3/2tanx - 3/2 = 0interval 0 to 2 pi exact answers and formula for the general solution as
    1. answers icon 1 answer
    2. don asked by don
    3. views icon 465 views
  7. cosxtanx-sin^2x=0solve for x over the domain 0 is less than or equal to x which is less than or equal to 2pi
    1. answers icon 2 answers
    2. lilpump asked by lilpump
    3. views icon 2,165 views
  8. Determine the derivative for y=tanxcosxa) y'=-sinxtanx + cosxsec^2x b) y'=-sinxtanx + cosxtanx c) y'=cosxsec^2x d) y'=sinx -
    1. answers icon 2 answers
    2. Melinda asked by Melinda
    3. views icon 608 views
  9. Simplify #3:[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
    1. answers icon 1 answer
    2. Anonymous asked by Anonymous
    3. views icon 1,054 views