y= -2cos(pi/6) + 8 whats

  1. y= -2cos(pi/6) + 8whats the maximum and minimum?
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    2. tom asked by tom
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  2. y= -2cos(pi/6) + 8whats the maximum and minimum?
    1. answers icon 2 answers
    2. tom asked by tom
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  3. cosA= 5/9 find cos1/2Aare you familiar with the half-angle formulas? the one I would use here is cos A = 2cos^2 (1/2)A - 1 5/9 +
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    2. Anonymous asked by Anonymous
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  4. What am I doing wrong?Equation: sin2x = 2cos2x Answers: 90 and 270 .... My Work: 2sin(x)cos(x) = 2cos(2x) sin(x) cos(x) =
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    2. Anonymous asked by Anonymous
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  5. Determine the solution of the equetion: 2cos x-1=0? 2cos x=0? and 2cos x+1=0?
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    2. Miley asked by Miley
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  6. how does 2cos(2x)-2cos(x)sin(x) becomes 2cos(2x)-sin(2x)? Try to explain each step simply.
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  7. Identify the equation for the following graph: (1 point) Responses y=2cos(2x) y is equal to 2 cosine 2 x y=−2cos(2x) y is
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  8. Multiply then use fundamental identities to simplify the expression below and determine which of the following is not equivalent
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    2. Tristian asked by Tristian
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  9. Which cosine function has maximum of 2, a minimum of -2, and a period of 2pi/3?Choose from answers below, correct one please. y
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  10. verify the identitysin x(1 - 2 cos^2 x + cos^4 x) = sin^5 x 1-2cos^2 x looks like 2cos^2x-1 its just backwards. I am not sure
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    2. Hannah asked by Hannah
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