x×sin^3A=y , cos^3A = sinA

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  1. Please help with this one. I've worked it out in so many ways and can't tell what's correct.sinA sinA ----- - ------ 1+sinA
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    2. Jasmine asked by Jasmine
    3. views icon 665 views
  2. Hi, can someone give me the answer to this question:secA-tanA=1/4. Find cosA I got: CosA=4(1-sinA) Is my answer good? Now
    1. answers icon 2 answers
    2. Shym asked by Shym
    3. views icon 904 views
  3. In any angle ABC prove that the perimeter = a/Sin A(Sin A + Sin B + Sin C)Start with perimeter = a+b+c but b= aSinB/sinA and c=
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    2. Anonymous asked by Anonymous
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  4. Hello I am having trouble with proving this:sinA/secA+secA/cscA = tan(A)(2-sin^2(A)) So far I've gotten SinA/(1/cosA) +
    1. answers icon 1 answer
    2. Jimbo asked by Jimbo
    3. views icon 784 views
  5. find all solutions in the interval [0,2 pi)sin(x+(3.14/3) + sin(x- 3.14/3) =1 sin^4 x cos^2 x Since sin (a+b) = sina cosb + cosb
    1. answers icon 1 answer
    2. lauren asked by lauren
    3. views icon 836 views
  6. Verify/prove the following:(sinA+tanA)/(1+secA) = sinA ______________________________ tanu = 1+sinu-cos^2u/cosu(1+sinu)
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    2. Kid asked by Kid
    3. views icon 715 views
  7. Prove that [sinA/(1-cosA)-(1-cosA)/sinA]*[cosA/(1+sinA)+(1+sinA)/cosA]=4cosecAI the second part as 2 secA
    1. answers icon 1 answer
    2. Agastya asked by Agastya
    3. views icon 717 views
  8. Let P=(cosA sinA)(sinA cosA) Q=(cosB sinA) (sinB cosA) show that PQ=(cosA(A-B) sin(A B)) (sinA(A B) cos(A-B))
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    2. James asked by James
    3. views icon 699 views
  9. Triangle HAV has <H = 124, a=8.5mm, and h=7.2mmHow many solutions are there? What I attempted: SinH/h=SinA/a Sin124/7.2=SinA/8.5
    1. answers icon 2 answers
    2. AlphaPrimes asked by AlphaPrimes
    3. views icon 626 views
  10. if 5cos A plus 3=0 and 180<A<360..without using a calculator and with the aid of a diagram,determine the value of 1.1 sinA plus
    1. answers icon 1 answer
    2. patience morakile asked by patience morakile
    3. views icon 1,085 views