x^3(sinx)/ 5cosx

Prove the following:[1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)]
1. 3 answers
2. asked by Anonymous
3. 1,006 views
2(sinx)^2-5cosx-4=0
1. 1 answer
2. asked by Anonymous
3. 439 views
x^3(sinx)/ 5cosx
1. 0 answers
2. asked by jnky
3. 557 views
y = x^3 sinx / 5cosx
1. 1 answer
2. asked by jnky
3. 481 views
2(sinx)^2-5cosx-4=0Solve for all solutions between [0,2pi]
1. 2 answers
2. asked by Anonymous
3. 825 views
Mathematics - Trigonometric Identities - Reiny, Friday, November 9, 2007 at 10:30pm(sinx - 1 -cos^2x) (sinx + 1 - cos^2x) should
1. 3 answers
2. asked by Anonymous
3. 831 views
Compute inverse functions to four significant digits.cos^2x=3-5cosx rewrite it as.. cos^2x + 5cosx -3=0 now you have a
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2. asked by Kate
3. 677 views
Simplify sin x cos^2x-sinxHere's my book's explanation which I don't totally follow sin x cos^2x-sinx=sinx(cos^2x-1)
1. 1 answer
2. asked by Tara
3. 1,103 views
Compute inverse functions to four significant digits.cos^2x=3-5cosx cos^2x + 5cosx -3=0 now you have a quadratic, solve for cos
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2. asked by Kate
3. 617 views
Hello! Can someone please check and see if I did this right? Thanks! :)Directions: Find the exact solutions of the equation in
1. 1 answer
2. asked by Maggie
3. 904 views