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x^2-5x=-10= x=5+i sqrt15/2,5-i sqrt15/2 Did
Simpilfy the radical expression by rationalzing the denoiminator?
3/sqrt15 a)sqrt45/15 b)sqrt15/5 c)5sqrt15*** d)sqrt3
3 answers
asked by
Angel
696 views
x^2-5x=-10 =x=5+i sqrt15/2 ,5-i sqrt15/2.
CAN SOMEONE CHECK MY ANSWER.
2 answers
asked by
Cynthia
478 views
Solve:25x^4-20x^2+3=0 =(sqrt5/5),-(sqrt5/5),(sqrt15/5),(-sqrt15/5).
Can you tell me which one is correct.This is a second post to
1 answer
asked by
Anne
403 views
If sin theta= -7/8, then the value of 1/cot theta in the interval 3pi/2<theta is? okay I've done this question twice. The 1st
1 answer
asked by
Tye
500 views
If cos A = 1/3 with 0 < A< pi/2, and sinB=1/4, with pi/2<B<pi. calculate cos(A+B).
My answer is (-sqrt15-2sqrt2)/12 But the back
1 answer
asked by
Halle
1,396 views
x^2-5x=-10= x=5+i sqrt15/2,5-i sqrt15/2
Did I get this right.
1 answer
asked by
Cindy
390 views
Remove the radical from the denominator below. Do not simplify the answer.
-2 sqrt15 / (6- sqrt13)
1 answer
asked by
lindsey
908 views
How do I work this to get the answer because I am stuck. Help, Help, please anyone. Ihope that you are able to understand what I
2 answers
asked by
kenneth
556 views
The product if 5sqrt27 and ___ would yield a rational number.
A. sqrt12 B. sqrt9 C. 4sqrt2 D. sqrt15
1 answer
32 views
The product of 5sqrt27 and BLANK would yield a rational number.
a. sqrt12 b.sqrt9 c.4 sqrt2 d.sqrt15
1 answer
14 views