x^2-5x=-10= x=5+i sqrt15/2,5-i sqrt15/2 Did

  1. Simpilfy the radical expression by rationalzing the denoiminator?3/sqrt15 a)sqrt45/15 b)sqrt15/5 c)5sqrt15*** d)sqrt3
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    2. Angel asked by Angel
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  2. x^2-5x=-10 =x=5+i sqrt15/2 ,5-i sqrt15/2.CAN SOMEONE CHECK MY ANSWER.
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    2. Cynthia asked by Cynthia
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  3. Solve:25x^4-20x^2+3=0 =(sqrt5/5),-(sqrt5/5),(sqrt15/5),(-sqrt15/5).Can you tell me which one is correct.This is a second post to
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    2. Anne asked by Anne
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  4. If sin theta= -7/8, then the value of 1/cot theta in the interval 3pi/2<theta is? okay I've done this question twice. The 1st
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    2. Tye asked by Tye
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  5. If cos A = 1/3 with 0 < A< pi/2, and sinB=1/4, with pi/2<B<pi. calculate cos(A+B).My answer is (-sqrt15-2sqrt2)/12 But the back
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    2. Halle asked by Halle
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  6. x^2-5x=-10= x=5+i sqrt15/2,5-i sqrt15/2Did I get this right.
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    2. Cindy asked by Cindy
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  7. Remove the radical from the denominator below. Do not simplify the answer.-2 sqrt15 / (6- sqrt13)
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    2. lindsey asked by lindsey
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  8. How do I work this to get the answer because I am stuck. Help, Help, please anyone. Ihope that you are able to understand what I
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    2. kenneth asked by kenneth
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  9. The product if 5sqrt27 and ___ would yield a rational number.A. sqrt12 B. sqrt9 C. 4sqrt2 D. sqrt15
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  10. The product of 5sqrt27 and BLANK would yield a rational number.a. sqrt12 b.sqrt9 c.4 sqrt2 d.sqrt15
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