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write π¦ = 3cos (2
The graph of r(t)=<t- 3sin(t)/2,1- 3cos(t)/2,t> For which values of t is the curvature largest?
I donβt know why my answer is
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#1
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How does β(-3cos(t)/2)^2 +(3sin(t)/2)^2 (3cos(t)/2 - 9/2)^2 equal 3/4β4sin^2(t)-12cos(t)+17 instead of βcos^2(t)
1 answer
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Anonymous
393 views
determine the amplitude and period for each function: y=4sin x, y=2sin4x,y=-3sin2pi x, y=-3cos x, y=-3cos pi over 2 x
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anonymous
506 views
Directions: Find the Location on Unit Circle, Period & General Solution for this problem>>>>>>> sin^2x=3cos^2x
What I have so
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asked by
Rachel
710 views
could somebody tell me the answer or order of operations to this calculation.
3cos(2 x 2) thanks. I assume you meant 3cos(2xΒ²)
0 answers
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r. giggs
1,021 views
write π¦ = 3cos (2 (π₯ -45)) β 4 in mapping notation
1 answer
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Solve the equation for solutions in the interval 0<=theta<2pi
Problem 1. 3cot^2-4csc=1 My attempt: 3(cos^2/sin^2)-4/sin=1
2 answers
asked by
Renee
1,694 views
Hello! I have this problem:
x(dx)/sqrt(9-x^2) I was wondering why I can't use trig substitution and substitute sqrt(9-x^2) for
1 answer
asked by
Lucy
718 views
Solve for x on the interval [0,Ο/2):
cos^3(2x) + 3cos^2(2x) + 3cos(2x) = 4 I havent done trig for a while so what exactly does
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jacob
1,053 views
4. Write the equation of the cosine function with an amplitude of 1/3, a period of 2pi, and a phase shift of 3pi/2.
I got
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Lauren
633 views