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two collinear harmonic oscillation x1=8sin(100pie(t))
two collinear harmonic oscillation x1=8sin(100pie(t)) and x2=12sin(96pie(t)) are superposed.calculate the value of time when the
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Jkss
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two collinear harmonic oscillation x1=8sin(100pie(t)) and x2=12sin(96pie(t)) are superposed.calculate the *maximum and minimum
2 answers
asked by
Jkss
596 views
two collinear harmonic oscillation x1=8sin(100pie(t)) and x2=12sin(96pie(t)) are superposed.calculate the
*maximum and minimum
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ashley
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two collinear harmonic oscillations are X1= 8 sin( 100pi *t) and X2= 12 sin(96 pi *t) are superposed. calculate the values of
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Pavan s m
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consider a simple harmonic oscillation with m=0.5kg,k=10N/m and amplitude A=3cm,if the oscillation is released from rest at x=A
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kabelo
588 views
A spring with a mass on it is oscillating with simple harmonic motion. If its frequency of oscillation is 5 Hz, how long does it
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Mia
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Consider a simple harmonic oscillation with m=0.5kg, k=10N/m and amplitude A=3cm. What is the total energy of the oscillation?
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Mpho mj
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Material point is accomplishing harmonic oscillation. What is the time for its displacement from equilibrium position to half of
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Ivan
477 views
The period of oscillation of a particle executing simple harmonic motion is 4(22/7) seconds. If the amplitude of oscillation is
1 answer
70 views
The period of oscillation of a particle executing or undergoing simple harmonic motion is 45 sec if the amplitude of the
1 answer
80 views