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the tangent to the curve
Consider the curve defined by 2y^3+6X^2(y)- 12x^2 +6y=1 .
a. Show that dy/dx= (4x-2xy)/(x^2+y^2+1) b. Write an equation of each
3 answers
asked by
Taeyeon
2,336 views
original curve: 2y^3+6(x^2)y-12x^2+6y=1
dy/dx=(4x-2xy)/(x^2+y^2+1) a) write an equation of each horizontal tangent line to the
1 answer
asked by
Craig
987 views
original curve: 2y^3+6(x^2)y-12x^2+6y=1
dy/dx=(4x-2xy)/(x^2+y^2+1) a) write an equation of each horizontal tangent line to the
0 answers
asked by
Rainie
695 views
original curve: 2y^3+6(x^2)y-12x^2+6y=1
dy/dx=(4x-2xy)/(x^2+y^2+1) a) write an equation of each horizontal tangent line to the
3 answers
asked by
stephanie
1,994 views
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