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tanA/secA-1 + tanA/secA+1 = 2
Prove the identity:
tanA/secA+1 = secA-1/tanA Can u please explainit to me step by step? I greatly appreciate your help! Thanks:)
2 answers
asked by
Kristien
598 views
(secA + tanA-1)(secA-tanA+1)=2tanA
1 answer
asked by
Bibek
307 views
1÷(tana-seca)-(1÷tana-seca)=-2sec
1 answer
asked by
Mohani updirizak
144 views
tanA/secA-1 + tanA/secA+1 = 2 cosecA
2 answers
asked by
sakeena
583 views
if secA-tanA =10 than sinA =?,cosA =?,secA =?
1 answer
asked by
Anonymous
716 views
Prove the identity tanA/secA+1 + cotA/cosecA+1=cosecA+secA -secAtanA
1 answer
asked by
vsjavsj
630 views
Verify/prove the following:
(sinA+tanA)/(1+secA) = sinA ______________________________ tanu = 1+sinu-cos^2u/cosu(1+sinu)
1 answer
asked by
Kid
781 views
(secA+tanA)(1-sinA)
1 answer
asked by
Mohd.Zaid
459 views
Prove that
[1+cotA-CosecA] [1+tanA+secA] = 2
2 answers
asked by
kumar
1,706 views
TanA=√2-1 then find secA.sinA+tan^2A-cosecA
1 answer
asked by
Shubham
742 views