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square root of (1-cosx/1+cosx) =
Simplify #3:
[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
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Anonymous
1,069 views
Verify the identity:
sin^(1/2)x*cosx - sin^(5/2)*cosx = cos^3x sq root sin x I honestly have no clue how to approach the
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Zee
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square root of (1-cosx/1+cosx) = cscx - cotx
prove the identity
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Manny
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hey, i would really appreciate some help solving for x when:
sin2x=cosx Use the identity sin 2A = 2sinAcosA so: sin 2x = cos x
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asked by
elle
712 views
I have a question relating to limits that I solved
lim(x-->0) (1-cosx)/2x^2 I multiplied the numerator and denominator by
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asked by
Alex
690 views
Trigonometric Identities
Prove: (tanx + secx -1)/(tanx - secx + 1)= tanx + secx My work so far: (sinx/cosx + 1/cosx +
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Dave
1,446 views
Verify the identity .
(cscX-cotX)^2=1-cosX/1+cosX _______ sorry i cant help you (cscX-cotX)=1/sinX - cosX/sinX = (1-cosX)/sinX If
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Rose
718 views
sin2x+cosx=0 , [-180,180)
= 2sinxcosx+cosx=0 = cosx(2sinx+1)=0 cosx=0 x1=cos^-1(0) x1=90 x2=360-90 x2=270 270 doesn't fit in
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asked by
Anonymous
913 views
Solve this equation fo rx in the interval 0<=x<=360
3sinxtanx=8 I would do it this way: sinxtanx = 8/3 sinx(sinx/cosx)=8/3
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asked by
Edward
976 views
I can't seem to prove these trig identities and would really appreciate help:
1. cosx + 1/sin^3x = cscx/1 - cosx I changed the 1:
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asked by
Heather
1,275 views