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sqrt50/sqrt2 sqrt50/sqrt2 = sqrt(25) =
sqrt50/sqrt2
sqrt50/sqrt2 = sqrt(25) = 5 I got the same answer which is 5
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asked by
Margie
460 views
sqrt50/sqrt2
(sqrt50)/(sqrt2)*(sqrt2/sqrt2)= (sqrt50*sqrt2)/2 =sqrt100/2=10/2=5 Check my thinking. thanks... what does this
0 answers
asked by
margie
838 views
Last question.
How do I add 2*SQRT50+7*SQRT2
3 answers
asked by
Anonymous
831 views
Is this correct:
sqrt2/sqrt10=sqrt2/5sqrt2 nope. it would be sqrt2/(sqrt5)(sqrt2) no.d sqrt2/sqrt10= sqrt (2/10)= sqrt (1/5) sqrt
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asked by
margie
798 views
change 50 to 25*2
sqrt 50 = 5 sqrt2 change 8 to 4*2 Nope: (sqrt3-sqrt5)(sqrt3-sqrt5). remember (a-b)(a-b)= a^2-2ab + b^2
0 answers
asked by
bobpursley
667 views
Assume that no denominator equals 0.
sqrt12 - sqrt18 + 3sqrt50 + sqrt75 = (sqrt2^2*3) - (sqrt2*3^2) + (3sqrt2*5^2) + (sqrt3*5^2)
1 answer
asked by
Jon
715 views
Given: f(x) = X^2-x
evaluate: f(sqrt2 + 3) I have worked out this and am stuck: (sqrt2+3)^2 - (sqrt2+3) (sqrt2+3)*(sqrt2+3)-
2 answers
asked by
Steve
602 views
Can someone please check my work on this problem? For some reason, I get the feeling that I did it wrong.
sqrt=square root (by
0 answers
asked by
Whitney
729 views
Hi--can anybody show me how to do this?
Find the length of the curve r(t)= (sqrt2)i + (sqrt2)j + (1-t^2)k from (0,0,1) to (sqrt2,
1 answer
asked by
Madison
552 views
I have tried solving this problem over and over but I'm still not sure with my answer.
The question is sqrt2 / 2 + sqrt2. I think
3 answers
asked by
Tommy
521 views