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solve the equation 1+4sin(x)=4cos^2(x)
Solve the equation for solutions in the interval 0<=theta<2pi
Problem 1. 3cot^2-4csc=1 My attempt: 3(cos^2/sin^2)-4/sin=1
2 answers
asked by
Renee
1,694 views
Which equation would the table of values represent? 0, 3 pi over 2, 3 pi, 9 pi over 2, 6 pi. 0, 4, 0, -4, 0 (1 point) Responses
1 answer
82 views
solve the equation
1+4sin(x)=4cos^2(x)
2 answers
asked by
bandit5571
440 views
Write an equation for simple harmonic motion, given that the amplitude equals 4 inches and the period equals 2 seconds and the
1 answer
asked by
Kayla
521 views
Solve the following Trigonometric equations, where 0 <= x <= 2π
a) sin^2 θ-1 = 0 b) cos2θ=1 c) 4sin^2 θ-3 = 0 d) 2cos^3 - cos
1 answer
asked by
Muneer
392 views
Convert the polar equation to rectangular form.
r=4cos-4sin What I have so far: r^2=4rcos-4rsin x^2+y^2-4x+4y x^2-4x+y^2+4y=0
1 answer
asked by
Amb
937 views
cos@-4SIN@=1 then sin@+4cos@=
1 answer
asked by
bhavya
507 views
Solve the equation 4sin^2 thiter +4cos thiter=5 for 0 degrees<=thiter<=360 degrees, give your answer in degrees
1 answer
107 views
(3-4sin^2A)(1-3tan^2A) =(3-tan^2A)(4cos^A-3)
0 answers
asked by
Shreya
755 views
(3-4sin^2a)(1-3tan^2a)=(3-tan^2a)(4cos^2a-3)
1 answer
asked by
Optional
880 views