solve for x 22x-5=102x−5=10

The question simply states-solve.-x^4+200=102x^2 I rearranged the equation so that I have x^-102x^2+200=0 Since I cannot factor
1. 4 answers
2. asked by Lucy
3. 686 views
Solve: -x^4 + 200 = 102x^2-x^4-102x^2+200=0 (-x^2)^2-102(x^2)+200=0 (x^2-51)(x^2+51)(x-20)(x-10) I'm stuck at this point
1. 1 answer
2. asked by Jon
3. 589 views
solve for x 22x-5=102x−5=10
1. 1 answer
2. 92 views
Solve: -x^4 + 200 = 102x^2
1. 2 answers
2. asked by Jon
3. 483 views
Which of the following systems of equations is equivalent to the system given below?4x+9y=102x+3y=12(1
1. 1 answer
2. asked by Smartypants
3. 21 views
Solve: -x^4 + 200 = 102x^2I know the last line was wrong I just took a guess on factoring it out. I just knew how to do the
1. 2 answers
2. asked by Jon
3. 543 views
15x^2-102x=3_____________ 7
1. 1 answer
2. asked by theo
3. 499 views
is this equation false?22x-5=102x−5=10
1. 1 answer
2. 118 views
which equation is false 1.3x+2=83x+2=8 or 22x-5=102x−5=10
1. 1 answer
2. 73 views
which equation is false 1.3x+2=83x+2=8 or 22x-5=102x−5=10
1. 5 answers
2. 72 views