Ask a New Question
Search
solve for unknown: log9 r=3/2
using logarithms to solve exponential equations.
5^1+x = 2^1-x I need exact numbers. I did one on my own already. 5^x-1 = 9 5^x-1
1 answer
asked by
Joe
762 views
using logarithms to solve exponential equations.
5^1+x = 2^1-x I need exact numbers. I did one on my own already. 5^x-1 = 9 5^x-1
4 answers
asked by
Joe
660 views
solve for unknown:
log9 r=3/2 logG 2=1/3 Can you show me the steps how to solve this problems.Thank yo very much for your time
2 answers
asked by
sandy
757 views
Algebraically determine the value(s) of x: log9(x-5)=1-log9(x+3)
Please help me. Thanks!
1 answer
asked by
Hannah
392 views
Solve:
(log2 8)^x - (log9 3)^x+1 = 0
7 answers
asked by
Cyn
658 views
solve log9(x-y)=log3(x+y
3 answers
asked by
kelly
584 views
solve the equation log3
(2-3x) = log9 (6x^2-19x+2)
2 answers
asked by
gibbons1
930 views
solve log 3x + log9=0 round to nearest hyndredth if necessary
1 answer
asked by
jerson
922 views
Evaluate log9 162 - log9 (2/3)
3 answers
asked by
Raven
126 views
Solve the function
2(9^x) - 5(3^×) = 12 So what I did So far is changed it into log functions: 2(9^x) = 12 9^x = 6 Log9(6) = x
4 answers
asked by
Rose
541 views