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solve for sinx=cos2x (between 0

  1. Hello! Can someone please check and see if I did this right? Thanks! :)Directions: Find the exact solutions of the equation in
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    2. Maggie asked by Maggie
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  2. Solve the equation of the interval (0, 2pi)cosx=sinx I squared both sides to get :cos²x=sin²x Then using tri indentites I came
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    2. Brian asked by Brian
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  3. the problem is2cos^2x + sinx-1=0 the directions are to "use an identity to solve each equation on the interval [0,2pi). This is
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    2. alex asked by alex
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  4. Please help!!!!!!!!!!! Find all solutions to the equation in the interval [0,2π).8. cos2x=cosx 10. 2cos^2x+cosx=cos2x Solve
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    2. Anonymous asked by Anonymous
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  5. cos2x-sinx=0. Factor and solve for sinx
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    2. anon asked by anon
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  6. solve for (<_ = less than or equal to / pie = pie sign / -pie = negative pie)3 sin²x = cos²x ; 0 <_ x < 2pie cos²x - sin²x =
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    2. Julie asked by Julie
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  7. solve for sinx=cos2x (between 0 and 2pi)
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    2. rachel asked by rachel
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  8. solve Sinx=Cos2x-1 for 0¡Üx<2¦Ð
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    2. dfg asked by dfg
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  9. Solve Sinx=Cos2x-1 for all values between 0 and 2pi
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    2. dfg asked by dfg
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  10. Where do I start to prove this identity:sinx/cosx= 1-cos2x/sin2x please help!! Hint: Fractions are evil. Get rid of them. Well,
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    2. maria asked by maria
    3. views icon 825 views