solve algebreically the equation cos2x=1-sinx

solve algebreically the equationcos2x=1-sinx also cosx=cosx-1 and please also sin2x=3sinx
1. 1 answer
2. asked by adil ahmed
3. 664 views
Solve the equation of the interval (0, 2pi)cosx=sinx I squared both sides to get :cos²x=sin²x Then using tri indentites I came
1. 4 answers
2. asked by Brian
3. 820 views
Hello! Can someone please check and see if I did this right? Thanks! :)Directions: Find the exact solutions of the equation in
1. 1 answer
2. asked by Maggie
3. 873 views
the problem is2cos^2x + sinx-1=0 the directions are to "use an identity to solve each equation on the interval [0,2pi). This is
1. 3 answers
2. asked by alex
3. 887 views
Please help!!!!!!!!!!! Find all solutions to the equation in the interval [0,2π).8. cos2x=cosx 10. 2cos^2x+cosx=cos2x Solve
1. 5 answers
2. asked by Anonymous
3. 869 views
Solve for x in the equation 2sin²x-1=cos²x+sinx
1. 1 answer
2. 55 views
Can someone please help me with this?Find all solutions to the equation in the interval [0,2pi) cos2x=sinx I know I have to use
1. 3 answers
2. asked by mary
3. 741 views
cos2x-sinx=0. Factor and solve for sinx
1. 5 answers
2. asked by anon
3. 676 views
solve for (<_ = less than or equal to / pie = pie sign / -pie = negative pie)3 sin²x = cos²x ; 0 <_ x < 2pie cos²x - sin²x =
1. 3 answers
2. asked by Julie
3. 1,096 views
Solve the equation 2cos2x = √3 for 0°≤x≤360°I did this: cos2x = √3 /2 2x=30 x=15 x=15, 165, 195, 345 Is this correct?
1. 1 answer
2. asked by Autumn
3. 1,815 views