solve 2tanx cos2x+1=tan3x+2cos2x

  1. solve 2tanx cos2x+1=tan3x+2cos2x
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    2. Season asked by Season
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  2. Solve : 2tan3x+cos2x+1=tan3x+2cos2x
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    2. Bishal Poudel asked by Bishal Poudel
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  3. Solve the equation of the interval (0, 2pi)cosx=sinx I squared both sides to get :cos²x=sin²x Then using tri indentites I came
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    2. Brian asked by Brian
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  4. Solve the equation 2cos2x = √3 for 0°≤x≤360°I did this: cos2x = √3 /2 2x=30 x=15 x=15, 165, 195, 345 Is this correct?
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    2. Autumn asked by Autumn
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  5. Solve sin2x + sin4x = cos2x + cos 4x for x in the interval[0,2pi)Hint: the following substitution should come in handy: sin3x=
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    2. greg asked by greg
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  6. Prove the identity:1-cos2x/sin2x = 1+tanx/1+cotx I simplified the RS to tanx. LS:(1-2cos²x+1)/2sinxcosx (2+2cos²x)/2sinxcosx
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    2. sh asked by sh
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  7. Prove the identityCos²x - sin²x = 2cos²x - 1
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  8. Rewrite the following expression in terms of tan3x: (sin2x + sin4x)/(cos2x + cos4x)
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    2. Josh asked by Josh
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  9. q1) 2cos2x is f(x)-square root3 is g(x) solve f(x)-g(x)=0 to get points of intersection in x is between 0 and 180degrees q2) a)
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    2. MR MATHEW MATICS asked by MR MATHEW MATICS
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  10. Solve identity,(1-sin2x)/cos2x = cos2x/(1+sin2x) I tried starting from the right side, RS: =(cos²x-sin²x)/(1+2sinxcosx)
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    2. sh asked by sh
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