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solve: log base2(log basex(x+6)=1 There's
solve: log base2(log basex(x+6)=1
There's 2 different bases, how do I solve for x?
0 answers
asked by
cyn
445 views
Help me solve this question by using 1's complement
(i) 110(Base2) - 010(Base2) (ii) 1010(Base2) - 1000(Base2) Help me solve this
0 answers
asked by
Rushab
999 views
How would I solve the equation: log(base2)4 - log(base2)(x+3) = log(base2)8 ?
i think i have to start by doing 4/(x+3)=8
2 answers
asked by
Ana
466 views
log(base2)x-log(base2)6= log(base2)5+ 2log(base2)3
log(x/6)=3log15 (x/6)=15^3 6*(x/6)=15^3*6 x=15^3*6 =20,250 Answer is 270....
1 answer
asked by
Melinda
570 views
solve the equation:
log(base2)^(x-3)log(base2)^5 = 2log(base2)^10 I don't know how to solve it, can someone help me? Please and
3 answers
asked by
Ana
533 views
Find the second derivative of the following function:
y=log(base2)x/x² y'=[(x/ln2)-2xlog(base2)x]/x^4 the derivative of x/ln2 is
2 answers
asked by
sh
597 views
In the logarithmic expression . . . log(base 4) 8 , how does the base 4 become base 2?
Here is how it is suppose to be worked
0 answers
asked by
Megan
520 views
Given that 2 log base2 (x+15) - log base2 x = 6
1.Show that x^2 -34x +225 = 0 2. Hence or otherwise solve the equation 2 log base
1 answer
asked by
lindsay
2,732 views
how to solve log basex 8=-1/2
pls help
2 answers
asked by
ted
402 views
how to solve log basex 8=-1/2
pls help
1 answer
asked by
ted
380 views