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sinx cscx-sin^(2)x=cos^(2)x
My previous question:
Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) =
2 answers
asked by
Jon
919 views
Find a numerical value of one trigonometric function of x if
tanx/cotx - secx/cosx = 2/cscx a) cscx=1 b) sinx=-1/2 c)cscx=-1
1 answer
asked by
Lucy
957 views
Prove the following:
[1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)]
3 answers
asked by
Anonymous
938 views
express in sinx
1 1 ---------- + -------- cscx + cotx cscx - cotx and express in cosx 1 + cot x ------- - sin^2x cscx = 1/sinx so
0 answers
asked by
linds
776 views
express this in sinx
(1/ cscx + cotx )+ (1/cscx- cotx) i got 2sinx is that right?? and B) express in cosx problem: is 1 +
1 answer
asked by
linds
1,399 views
Varify the identity cscx(cscx-sinx)+sinx-cosx/sinx + cot?
1 answer
asked by
clarence
466 views
We are doing trig identities in school. I need help with these five:
1.1+sinx/1-sinx=cscx+1/cscx-1 2.tanx+sinx/1+cosx=tanx
1 answer
asked by
Jay
953 views
Simplify #1:
cscx(sin^2x+cos^2xtanx)/sinx+cosx = cscx((1)tanx)/sinx+cosx = cscxtanx/sinx+cosx Is the correct answer
1 answer
asked by
Anonymous
1,348 views
Simplify #1:
cscx(sin^2x+cos^2xtanx)/sinx+cosx = cscx((1)tanx)/sinx+cosx = cscxtanx/sinx+cosx Is the correct answer
4 answers
asked by
Anonymous
1,949 views
hello
i know that deriv(cscx) = -cscxcotx and that deriv(cos) = -sinx deriv(cotx) = -((cscx)^2) my question is: is this
1 answer
asked by
CALLIE CALC
655 views