sinx cscx-sin^(2)x=cos^(2)x

  1. My previous question:Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) =
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    2. Jon asked by Jon
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  2. Find a numerical value of one trigonometric function of x iftanx/cotx - secx/cosx = 2/cscx a) cscx=1 b) sinx=-1/2 c)cscx=-1
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    2. Lucy asked by Lucy
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  3. Prove the following:[1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)]
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    2. Anonymous asked by Anonymous
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  4. express in sinx1 1 ---------- + -------- cscx + cotx cscx - cotx and express in cosx 1 + cot x ------- - sin^2x cscx = 1/sinx so
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    2. linds asked by linds
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  5. express this in sinx(1/ cscx + cotx )+ (1/cscx- cotx) i got 2sinx is that right?? and B) express in cosx problem: is 1 +
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    2. linds asked by linds
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  6. Varify the identity cscx(cscx-sinx)+sinx-cosx/sinx + cot?
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    2. clarence asked by clarence
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  7. We are doing trig identities in school. I need help with these five:1.1+sinx/1-sinx=cscx+1/cscx-1 2.tanx+sinx/1+cosx=tanx
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    2. Jay asked by Jay
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  8. Simplify #1:cscx(sin^2x+cos^2xtanx)/sinx+cosx = cscx((1)tanx)/sinx+cosx = cscxtanx/sinx+cosx Is the correct answer
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    2. Anonymous asked by Anonymous
    3. views icon 1,348 views
  9. Simplify #1:cscx(sin^2x+cos^2xtanx)/sinx+cosx = cscx((1)tanx)/sinx+cosx = cscxtanx/sinx+cosx Is the correct answer
    1. answers icon 4 answers
    2. Anonymous asked by Anonymous
    3. views icon 1,949 views
  10. helloi know that deriv(cscx) = -cscxcotx and that deriv(cos) = -sinx deriv(cotx) = -((cscx)^2) my question is: is this
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    2. CALLIE CALC asked by CALLIE CALC
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