sin2xcosx-sinx=0 interval(0,2pi)

sin2xcosx-sinx=0 interval(0,2pi)
1. 3 answers
2. asked by Anonymous
3. 1,347 views
Prove the identity(Sin²xcosx + cos³x) ÷ sinx = cotx
1. 1 answer
2. 81 views
Hello! Can someone please check and see if I did this right? Thanks! :)Directions: Find the exact solutions of the equation in
1. 1 answer
2. asked by Maggie
3. 834 views
sin3x=(sinx)(3-asin^2x)Wow! is that arcsin^2(x) ??? are we solving for x? or is it proving the identity? proving the identity
1. 0 answers
2. asked by abdo
3. 674 views
Prove the following:[1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)]
1. 3 answers
2. asked by Anonymous
3. 944 views
the problem is2cos^2x + sinx-1=0 the directions are to "use an identity to solve each equation on the interval [0,2pi). This is
1. 3 answers
2. asked by alex
3. 866 views
y= 2sin^2 xy=1- sinx find values of x inthe interval 0<x<360 if 2sin^x = 1-sinx this can be arranged into the quadratic. 2sin^2
1. 0 answers
2. asked by Candy
3. 648 views
Mathematics - Trigonometric Identities - Reiny, Friday, November 9, 2007 at 10:30pm(sinx - 1 -cos^2x) (sinx + 1 - cos^2x) should
1. 3 answers
2. asked by Anonymous
3. 782 views
f(x)= (1-sinx) interval (0≤x≤2π) find where the function is increasing decreasing..i know that f`(x)=1-sinx it is equal to
1. 1 answer
2. asked by help
3. 563 views
Determine the solutions for:(cos x)/(1 + sinx) + (1 + sinx)/(cosx) = 2 in the interval x is all real numbers, such that [-2 pi,
1. 1 answer
2. asked by Anonymous
3. 669 views