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sin²B - sin²Bcos²B
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sin²B - sin²Bcos²B
1 answer
asked by
mr o qamata
216 views
1. (1-sin²B)/(sin²Bcos²B)= csc²B-sec²B
--that's really the given. please help.
2 answers
asked by
anjelica318
582 views
Prove that
sin²A-sin²B/sinAcosA-sinBcosB = tan(A+B)
0 answers
asked by
Kewal
761 views
If A + B + C = 180° prove that
Sin2A + sin2B – sin2C = 4cosAcosBsinC
1 answer
asked by
Kewal
941 views
Prove that (1-sinb)/(1+sin2b)=tan^2(45-b) plz the b means beta???
2 answers
asked by
Collins
593 views
If A + B + C = π, prove that: ( sin2A + sin2B + sin2C ) / ( sinA + sinB + sinC ) = 8 sin(A/2) sin(B/2) sin(C/2)
2 answers
asked by
manish
908 views
If sin a + sinb + sinc = 4cosa/2cosb/2cosc/2
Then sin 2a + sin2b + sin 2c = 4cosacosbcosc
1 answer
asked by
Anonymous
506 views
Prove that in any triangle ABC Sin2A+Sin2B+Sin2C/SinA+SinB+SinC=8Sin(A/2)Sin(B/2)Sin(C/2)
1 answer
asked by
joel
1,038 views
Prove That Sin2A+SIN2B+SIN2C/SINA+SINB+SINC=8SinA/2SINB/2SINC/2
1 answer
asked by
joel
911 views
Prove That Sin2A+ Sin2B +SIN2C/sinA+SINB+SINC=8sinA/sinB/2COSC/2
1 answer
asked by
Joel
978 views
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