simplify (cos4x-cos2x)/(sin4x+sin2x) the answer choices

simplify (cos4x-cos2x)/(sin4x+sin2x) the answer choices are : cotx, tanx, cotxtanx, or 1
1. 1 answer
2. asked by Scott
3. 1,061 views
Simplify the expression using trig identities:1. (sin4x - cos4x)/(sin2x -cos2x) 2. (sinx(cotx)+cosx)/(2cotx)
1. 1 answer
2. asked by Tasha
3. 2,891 views
Prove the identityCos⁴x + sin²x = sin⁴x + cos²x
1. 1 answer
2. 127 views
Rewrite the following expression in terms of tan3x: (sin2x + sin4x)/(cos2x + cos4x)
1. 1 answer
2. asked by Josh
3. 1,123 views
veify that each equation is an identitycos2x+tan2xcos2x=1 sin4x-cos4x/sin2x=1-cot2x
1. 1 answer
2. asked by GIGI
3. 624 views
Simplify:(cosx + cos2x + cos3x + cos4x + cos5x + cos6x) / (sinx + sin2x + sin3x + sin4x + sin5x + sin6x) into a single Cotangent
1. 2 answers
2. asked by Jeff
3. 1,734 views
Solve identity,(1-sin2x)/cos2x = cos2x/(1+sin2x) I tried starting from the right side, RS: =(cos²x-sin²x)/(1+2sinxcosx)
1. 3 answers
2. asked by sh
3. 776 views
Been trying this forever so it says: Simplify 1+sin2x+cos2x/1+sin2x-cos2xive tried this problem so many times I need help with
1. 1 answer
2. asked by Maria
3. 1,562 views
Find all solutions to the equation in the interval [0, 2pi)cos4x-cos2x=0 So,this is what i've done so far: cos4x-cos2x=0
1. 1 answer
2. asked by Maria
3. 1,656 views
Evaluate the integral e^x sin4x dx.I know the answer is 1/17 e^x sin4x - 4/17 e^x cos4x + C but I don't know how to solve it
1. 1 answer
2. asked by Scott
3. 615 views