show that the equation 2x-1-sinx=0

Prove the following:[1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)]
1. 3 answers
2. asked by Anonymous
3. 938 views
Hello! Can someone please check and see if I did this right? Thanks! :)Directions: Find the exact solutions of the equation in
1. 1 answer
2. asked by Maggie
3. 831 views
Mathematics - Trigonometric Identities - Reiny, Friday, November 9, 2007 at 10:30pm(sinx - 1 -cos^2x) (sinx + 1 - cos^2x) should
1. 3 answers
2. asked by Anonymous
3. 778 views
tanx+secx=2cosx(sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 =
1. 0 answers
2. asked by shan
3. 978 views
the problem is2cos^2x + sinx-1=0 the directions are to "use an identity to solve each equation on the interval [0,2pi). This is
1. 3 answers
2. asked by alex
3. 863 views
Simplify sin x cos^2x-sinxHere's my book's explanation which I don't totally follow sin x cos^2x-sinx=sinx(cos^2x-1)
1. 1 answer
2. asked by Tara
3. 1,051 views
Sketch the graph of the given equation over the interval [-2π, 2π]y=sinx+5 Select.all the transformations that are
1. 1 answer
2. 97 views
Solving Trigonometic Equationssolve for x and give the answers as a equations : ( by radian) 1)cos(sinx)=1 <<<and thanks >>> We
1. 0 answers
2. asked by abdo
3. 679 views
hi, i need help solving this trigonometric equation:sinx+3cosx=0 i don't know what to do as i can't just diviide the two to
1. 0 answers
2. asked by elle
3. 592 views
Find an equation of the tangent line to the curve aty = cosx - sinx (pi, -1) I found y'= -sinx - cosx and used the equation of
1. 1 answer
2. asked by Daniel
3. 872 views