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secx/secx-tanx=sec^2x+ secx+tanx
Evaluate the integral of
(secx)^2 * (tanx)^3 *dx I started out with letting u=secx and du=secx*tanx*dx , but then I am kind of
1 answer
asked by
Dave
780 views
tan(3x) + 1 = sec(3x)
Thanks, pretend 3x equals x so tanx + 1 = secx we know the law that 1 + tanx = secx so tanx + 1 becomes
0 answers
asked by
Jen
3,914 views
How do you verify:
1.) sinxcosx+sinx^3secx=tanx 2.) (secx+tanx)/(secx-tan)=(secx+tanx)^2 I tried starting from the left on both
0 answers
asked by
Corin
885 views
I can't find the integral for
(tanx)^(6)*(secx)^(2) I tried splitting up tanx into (tanx)^2*(tanx)^4 and let the latter equal
0 answers
asked by
Anonymous
675 views
find dy/dx
y=ln (secx + tanx) Let u= secx + tan x dy/dx= 1/u * du/dx now, put the derivative of d secx/dx + dtanx/dx in. You may
1 answer
asked by
amy
1,585 views
Complete the following identity secx-1/secx=? I have four multiple choice options and can't seem to work my way to either one.
3 answers
asked by
Anne
781 views
Int tanx sec^2x dx can be taken as (by putting it in form of Int xdx)
Int secx.secx tanx dx=(sec^2x)/2 Int tanx.sec^2x
3 answers
asked by
Anonymous
786 views
find the derivative of f(x)=tanx-4/secx
I used the quotient rule and got (sec^2x-4)(secx)-(tanx-4)(cosx)/sec^2x but I'm pretty
3 answers
asked by
gnozahs
777 views
1/tanx-secx+ 1/tanx+secx=-2tanx
so this is what I did: =tanx+secx+tanx-secx =(sinx/cosx)+ (1/cosx)+(sinx/cosx)-(1/cosx)
0 answers
asked by
olivia
1,367 views
How do i get left side to equal rs?
(Tanx/1+secx)+(1+secx/tanx)=(2/sinx)
1 answer
asked by
Bobbie
571 views