secx/secx-tanx=sec^2x+ secx+tanx

  1. Evaluate the integral of(secx)^2 * (tanx)^3 *dx I started out with letting u=secx and du=secx*tanx*dx , but then I am kind of
    1. answers icon 1 answer
    2. Dave asked by Dave
    3. views icon 780 views
  2. tan(3x) + 1 = sec(3x)Thanks, pretend 3x equals x so tanx + 1 = secx we know the law that 1 + tanx = secx so tanx + 1 becomes
    1. answers icon 0 answers
    2. Jen asked by Jen
    3. views icon 3,914 views
  3. How do you verify:1.) sinxcosx+sinx^3secx=tanx 2.) (secx+tanx)/(secx-tan)=(secx+tanx)^2 I tried starting from the left on both
    1. answers icon 0 answers
    2. Corin asked by Corin
    3. views icon 885 views
  4. I can't find the integral for(tanx)^(6)*(secx)^(2) I tried splitting up tanx into (tanx)^2*(tanx)^4 and let the latter equal
    1. answers icon 0 answers
    2. Anonymous asked by Anonymous
    3. views icon 675 views
  5. find dy/dxy=ln (secx + tanx) Let u= secx + tan x dy/dx= 1/u * du/dx now, put the derivative of d secx/dx + dtanx/dx in. You may
    1. answers icon 1 answer
    2. amy asked by amy
    3. views icon 1,585 views
  6. Complete the following identity secx-1/secx=? I have four multiple choice options and can't seem to work my way to either one.
    1. answers icon 3 answers
    2. Anne asked by Anne
    3. views icon 781 views
  7. Int tanx sec^2x dx can be taken as (by putting it in form of Int xdx)Int secx.secx tanx dx=(sec^2x)/2 Int tanx.sec^2x
    1. answers icon 3 answers
    2. Anonymous asked by Anonymous
    3. views icon 786 views
  8. find the derivative of f(x)=tanx-4/secxI used the quotient rule and got (sec^2x-4)(secx)-(tanx-4)(cosx)/sec^2x but I'm pretty
    1. answers icon 3 answers
    2. gnozahs asked by gnozahs
    3. views icon 777 views
  9. 1/tanx-secx+ 1/tanx+secx=-2tanxso this is what I did: =tanx+secx+tanx-secx =(sinx/cosx)+ (1/cosx)+(sinx/cosx)-(1/cosx)
    1. answers icon 0 answers
    2. olivia asked by olivia
    3. views icon 1,367 views
  10. How do i get left side to equal rs?(Tanx/1+secx)+(1+secx/tanx)=(2/sinx)
    1. answers icon 1 answer
    2. Bobbie asked by Bobbie
    3. views icon 571 views