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A) How do you prove that if 0(<or=)x(<or=)10, then 0(<or=)sqrt(x+1)(<or=)10?
B) So once that is found, then how can you prove
4 answers
asked by
Sarita
989 views
A) How do you prove that if 0(<or=)x(<or=)10, then 0(<or=)sqrt(x+1)(<or=)10?
B) So once that is found, then how can you prove
0 answers
asked by
Sarita
786 views
A) How do you prove that if 0(<or=)x(<or=)10, then 0(<or=)sqrt(x+1)(<or=)10?
B) So once that is found, then how can you prove
0 answers
asked by
Sarita
743 views
A) How do you prove that if 0(<or=)x(<or=)10, then 0(<or=)sqrt(x+1)(<or=)10?
B) So once that is found, then how can you prove
0 answers
asked by
Sarita
1,157 views
A) How do you prove that if 0(<or=)x(<or=)10, then 0(<or=)sqrt(x+1)(<or=)10?
B) So once that is found, then how can you prove
2 answers
asked by
Sarita
845 views
Prove: [1/sqrt(2)] [sqrt(a) + sqrt(b)] <= sqrt(a + b) <= sqrt(a) + sqrt(b) for all non-negative real numbers a and b.
1 answer
asked by
Mirie
665 views
Evaluate sqrt7x (sqrt x-7 sqrt7) Show your work.
sqrt(7)*sqrt(x)-sqrt(7)*7*sqrt(7) sqrt(7*x)-7*sqrt(7*7) sqrt(7x)-7*sqrt(7^2)
1 answer
asked by
Alexa
3,171 views
Let a, b, and c be positive real numbers. Prove that sqrt(a^2 - ab + b^2) + sqrt(a^2 - ac + c^2) is greater or equal to sqrt(b^2
1 answer
asked by
Sam
1,248 views
sqrt 6 * sqrt 8
also sqrt 7 * sqrt 5 6.92820323 and 5.916079783 So you can see the steps — sqrt 6 * sqrt 8 = sqrt 48 sqrt 7 *
0 answers
asked by
Tina
706 views
A) How do you prove that if 0(<or=)x(<or=)10, then 0(<or=)sqrt(x+1)(<or=)10?
B) So once that is found, then how can you prove
8 answers
asked by
Sarita
655 views