original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy)/(x^2+y^2+1) a) write an equation of each

original curve: 2y^3+6(x^2)y-12x^2+6y=1dy/dx=(4x-2xy)/(x^2+y^2+1) a) write an equation of each horizontal tangent line to the
1. 1 answer
2. asked by Craig
3. 987 views
original curve: 2y^3+6(x^2)y-12x^2+6y=1dy/dx=(4x-2xy)/(x^2+y^2+1) a) write an equation of each horizontal tangent line to the
1. 3 answers
2. asked by stephanie
3. 1,994 views
original curve: 2y^3+6(x^2)y-12x^2+6y=1dy/dx=(4x-2xy)/(x^2+y^2+1) a) write an equation of each horizontal tangent line to the
1. 0 answers
2. asked by Rainie
3. 694 views
Please help this is due tomorrow and I don't know how to Ive missed a lot of school sickConsider the curve given by the equation
1. 1 answer
2. asked by Jessica Chaney
3. 1,320 views
1. Given the curvea. Find an expression for the slope of the curve at any point (x, y) on the curve. b. Write an equation for
1. 3 answers
2. asked by Fareha
3. 4,703 views
Consider the curve given by the equation y^3+3x^2y+13=0a.find dy/dx b. Write an equation for the line tangent to the curve at
1. 1 answer
2. asked by Little
3. 5,607 views
given the curve x + xy + 2y^2 = 6...a. find an expression for the slope of the curve. i got (-1-y)/(x + 4y) as my answer. b.
1. 5 answers
2. asked by jane
3. 4,184 views
1. Consider the curve y=x^2.a. write down (dy)/(dx) My answer: 2x The point P(3,9) lies on the curve y=x^2. b. Find the gradient
1. 2 answers
2. asked by Anonymous
3. 2,103 views
sketch the curve using the parametric equation to plot the points. use an arrow to indicate the direction the curve is traced as
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2. asked by Sammy
3. 664 views
(a) Graph the parameterized curve described by x = 2sint, y = -3cost, 0<= t <= pi. Indicate the direction in which the curve is
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2. asked by Kevin
3. 1,220 views