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log6=x and log8=y, determine an

  1. log6=x and log8=y, determine an expression for log3 in terms of x an y.
    1. answers icon 0 answers
    2. nat asked by nat
    3. views icon 652 views
  2. log27+log8-log128 and log6-log8
    1. answers icon 2 answers
    2. Evan asked by Evan
    3. views icon 248 views
  3. The problem I have to solve is log with base 2 ^6 multiply by log base 6 ^ 8.I use the change of base formula and got log6/log2
    1. answers icon 1 answer
    2. Shadow asked by Shadow
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  4. log(x-2) +log8 (x-4) =log6 (x-1)
    1. answers icon 2 answers
    2. Jeconiah asked by Jeconiah
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  5. Solve:Log5(x-2) + log8(x-4)= log6(x-1)
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    2. NR asked by NR
    3. views icon 982 views
  6. Solve for x: log5(x-2)+log8(x-4) = log6(x-1). I do not have any idea on this topic.
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    2. Seth asked by Seth
    3. views icon 637 views
  7. Solve for the value of x: log5(x-2)+log8(x-4)=Log6(x-1)..For your information that 5,8 and 6 are bases not just multipliers.
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    2. Seth asked by Seth
    3. views icon 522 views
  8. Simply the following as far as possible.1.log8 - log4*log6/log4 2.log8+log4
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    2. Sheik sudani Al Qatar La muktal. asked by Sheik sudani Al Qatar La muktal.
    3. views icon 422 views
  9. Ok feeling kinda dumb because this isn't coming out right. I know it's simple.log6 (x -3) + log6(x -6) - log6(x + 1) = 2
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    2. Anon asked by Anon
    3. views icon 423 views
  10. Expand the expression log(8x5) using the properties of logarithms.(1 point) Responses log8+logx log8+logx log8+logx−log5
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    2. pakyo asked by pakyo
    3. views icon 33 views