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log6=x and log8=y, determine an

  1. log6=x and log8=y, determine an expression for log3 in terms of x an y.
    1. answers icon 0 answers
    2. nat asked by nat
    3. views icon 674 views
  2. log27+log8-log128 and log6-log8
    1. answers icon 2 answers
    2. Evan asked by Evan
    3. views icon 260 views
  3. The problem I have to solve is log with base 2 ^6 multiply by log base 6 ^ 8.I use the change of base formula and got log6/log2
    1. answers icon 1 answer
    2. Shadow asked by Shadow
    3. views icon 1,076 views
  4. log(x-2) +log8 (x-4) =log6 (x-1)
    1. answers icon 2 answers
    2. Jeconiah asked by Jeconiah
    3. views icon 583 views
  5. Solve:Log5(x-2) + log8(x-4)= log6(x-1)
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    2. NR asked by NR
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  6. Solve for x: log5(x-2)+log8(x-4) = log6(x-1). I do not have any idea on this topic.
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    2. Seth asked by Seth
    3. views icon 660 views
  7. Solve for the value of x: log5(x-2)+log8(x-4)=Log6(x-1)..For your information that 5,8 and 6 are bases not just multipliers.
    1. answers icon 2 answers
    2. Seth asked by Seth
    3. views icon 539 views
  8. Simply the following as far as possible.1.log8 - log4*log6/log4 2.log8+log4
    1. answers icon 1 answer
    2. Sheik sudani Al Qatar La muktal. asked by Sheik sudani Al Qatar La muktal.
    3. views icon 441 views
  9. Ok feeling kinda dumb because this isn't coming out right. I know it's simple.log6 (x -3) + log6(x -6) - log6(x + 1) = 2
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    2. Anon asked by Anon
    3. views icon 452 views
  10. Expand the expression log(8x5) using the properties of logarithms.(1 point) Responses log8+logx log8+logx log8+logx−log5
    1. answers icon 1 answer
    2. pakyo asked by pakyo
    3. views icon 65 views