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log2(log4x) = 1 Solve the
solve the equation
log2(x+4)-log4x=2 the 2 and 4 are lower than the g This is what I got: log2(x+4)+log2(4^x)=2 log2((x+4)*4^x)=2
1 answer
asked by
anonymous
1,053 views
solve the equation.
log2(x+4)-log4x=2 please show work
1 answer
asked by
anonymous
363 views
I am having trouble figuring out how to solve these logarithms. Could someone please help!
log2(log4x)=1 and solve for x and y:
1 answer
asked by
Chloe
618 views
I am having trouble figuring out how to solve this logarithms. Could someone please help!
log2(log4x)=1 and solve for x and y:
0 answers
asked by
Chloe
1,193 views
I am having trouble figuring out how to solve these logarithms. Could someone please help!
log2(log4x)=1 and solve for x and y:
1 answer
asked by
Chloe
452 views
log2(log4x) = 1
Solve the equation The bases are 2 and 4 respectively, I'm just not sure how to signify that on the keyboard.
3 answers
asked by
Laura
1,981 views
i need help with these two homework problems
Use the Laws of Logarithms to combine the expression into a single logarithm log2 5
1 answer
asked by
Emma
830 views
1. Log10²x+log10x²=log10² 2-1
2. Log4(log2x)+log2(log4x)=2 3. X^logx+5/3= 10^5+log x 4. Log 1/2(x-1)+ log
1 answer
asked by
karan
1,072 views
solve log2(3x-1)-log2(x-1)=log2(x+1)
i have absolutely no idea how to solve this. can anyone help me, please?
1 answer
asked by
Kelly
536 views
Solve:
2^(5x-6) = 7 My work: log^(5x-6) = log7 5x - 6(log2) = log7 5x = log7 + 6(log2) x = (log7 + log2^6) / 5 And textbook
2 answers
asked by
Anonymous
1,230 views