log2(-3sinx)=2log2(cosx)+1 solve for x

log2(-3sinx)=2log2(cosx)+1 solve for x
1. 2 answers
2. asked by Sarah
3. 884 views
I am having trouble with a pre-cal problem. If you could explain how to do it that would be great!((3^3)^(cosx+2/3sinx))^2cosx+3
1. 1 answer
2. asked by Anonymous
3. 551 views
Can someone solve this and explain it please4^log2 (2log2 5)
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2. asked by Chuck
3. 661 views
1.Use the laws of logarithms to express log2 (6) â€“ log2 (3) + 2log2 (8)^1/2 as a single logarithm; then evaluate.2. For
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2. asked by alejandro
3. 810 views
solve the following logarithmic equation2log2(lower than g)^(x-2)+log2^2=3 x=?
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2. asked by ladybug,I need help please.
3. 368 views
solve algebreically the equationcos2x=1-sinx also cosx=cosx-1 and please also sin2x=3sinx
1. 1 answer
2. asked by adil ahmed
3. 645 views
Solve each equation for 0≤x<2π1. (cosX)(cosX+1)=0 2. 2sin^2(X)-3sinX=2
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2. asked by Leslie
3. 508 views
i need help with these two homework problemsUse the Laws of Logarithms to combine the expression into a single logarithm log2 5
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2. asked by Emma
3. 822 views
solve the equationlog2(x+4)-log4x=2 the 2 and 4 are lower than the g This is what I got: log2(x+4)+log2(4^x)=2 log2((x+4)*4^x)=2
1. 1 answer
2. asked by anonymous
3. 1,042 views
If y=3/(sinx+cosx) , find dy/dxA. 3sinx-3cosx B. 3/(sinx+cosx)^2 C. -3/(sinx+cosx)^2 D. 3(cosx-sinx)/(sinx+cosx)^2 E.
1. 1 answer
2. asked by Anonymous
3. 664 views